3x+4(x+5)=41

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Solution for 3x+4(x+5)=41 equation: 



3x+4(x+5)=41

We move all terms to the left:

3x+4(x+5)-(41)=0

We multiply parentheses

3x+4x+20-41=0

We add all the numbers together, and all the variables

7x-21=0

We move all terms containing x to the left, all other terms to the right

7x=21

x=21/7

x=3

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