3x+4(x-1)=3(x-4)+2

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Solution for 3x+4(x-1)=3(x-4)+2 equation: 



3x+4(x-1)=3(x-4)+2

We move all terms to the left:

3x+4(x-1)-(3(x-4)+2)=0

We multiply parentheses

3x+4x-(3(x-4)+2)-4=0



We calculate terms in parentheses: -(3(x-4)+2), so:

3(x-4)+2

We multiply parentheses

3x-12+2

We add all the numbers together, and all the variables

3x-10

Back to the equation:

-(3x-10)



We add all the numbers together, and all the variables

7x-(3x-10)-4=0

We get rid of parentheses

7x-3x+10-4=0

We add all the numbers together, and all the variables

4x+6=0

We move all terms containing x to the left, all other terms to the right

4x=-6

x=-6/4

x=-1+1/2

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