3x+4(x-2)=-1+8(2x+3)

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Solution for 3x+4(x-2)=-1+8(2x+3) equation: 



3x+4(x-2)=-1+8(2x+3)

We move all terms to the left:

3x+4(x-2)-(-1+8(2x+3))=0

We multiply parentheses

3x+4x-(-1+8(2x+3))-8=0



We calculate terms in parentheses: -(-1+8(2x+3)), so:

-1+8(2x+3)

determiningTheFunctionDomain
8(2x+3)-1

We multiply parentheses

16x+24-1

We add all the numbers together, and all the variables

16x+23

Back to the equation:

-(16x+23)



We add all the numbers together, and all the variables

7x-(16x+23)-8=0

We get rid of parentheses

7x-16x-23-8=0

We add all the numbers together, and all the variables

-9x-31=0

We move all terms containing x to the left, all other terms to the right

-9x=31

x=31/-9

x=-3+4/9

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