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3x+4(x-8)-x=2(3x-16)
We move all terms to the left:
3x+4(x-8)-x-(2(3x-16))=0
We add all the numbers together, and all the variables
2x+4(x-8)-(2(3x-16))=0
We multiply parentheses
2x+4x-(2(3x-16))-32=0
We calculate terms in parentheses: -(2(3x-16)), so:We add all the numbers together, and all the variables
2(3x-16)
We multiply parentheses
6x-32
Back to the equation:
-(6x-32)
6x-(6x-32)-32=0
We get rid of parentheses
6x-6x+32-32=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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