3x+4(x-8)-x=35(10x+15)

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Solution for 3x+4(x-8)-x=35(10x+15) equation: 



3x+4(x-8)-x=35(10x+15)

We move all terms to the left:

3x+4(x-8)-x-(35(10x+15))=0

We add all the numbers together, and all the variables

2x+4(x-8)-(35(10x+15))=0

We multiply parentheses

2x+4x-(35(10x+15))-32=0



We calculate terms in parentheses: -(35(10x+15)), so:

35(10x+15)

We multiply parentheses

350x+525

Back to the equation:

-(350x+525)



We add all the numbers together, and all the variables

6x-(350x+525)-32=0

We get rid of parentheses

6x-350x-525-32=0

We add all the numbers together, and all the variables

-344x-557=0

We move all terms containing x to the left, all other terms to the right

-344x=557

x=557/-344

x=-1+213/344

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