3x+4(x-8)-x=60(10x+15)

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Solution for 3x+4(x-8)-x=60(10x+15) equation: 



3x+4(x-8)-x=60(10x+15)

We move all terms to the left:

3x+4(x-8)-x-(60(10x+15))=0

We add all the numbers together, and all the variables

2x+4(x-8)-(60(10x+15))=0

We multiply parentheses

2x+4x-(60(10x+15))-32=0



We calculate terms in parentheses: -(60(10x+15)), so:

60(10x+15)

We multiply parentheses

600x+900

Back to the equation:

-(600x+900)



We add all the numbers together, and all the variables

6x-(600x+900)-32=0

We get rid of parentheses

6x-600x-900-32=0

We add all the numbers together, and all the variables

-594x-932=0

We move all terms containing x to the left, all other terms to the right

-594x=932

x=932/-594

x=-1+169/297

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