3x+4+11(x-2)=6(2x+1)

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Solution for 3x+4+11(x-2)=6(2x+1) equation: 



3x+4+11(x-2)=6(2x+1)

We move all terms to the left:

3x+4+11(x-2)-(6(2x+1))=0

We multiply parentheses

3x+11x-(6(2x+1))-22+4=0



We calculate terms in parentheses: -(6(2x+1)), so:

6(2x+1)

We multiply parentheses

12x+6

Back to the equation:

-(12x+6)



We add all the numbers together, and all the variables

14x-(12x+6)-18=0

We get rid of parentheses

14x-12x-6-18=0

We add all the numbers together, and all the variables

2x-24=0

We move all terms containing x to the left, all other terms to the right

2x=24

x=24/2

x=12

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