3x+4+2x-12=3(x+2)

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Solution for 3x+4+2x-12=3(x+2) equation: 



3x+4+2x-12=3(x+2)

We move all terms to the left:

3x+4+2x-12-(3(x+2))=0

We add all the numbers together, and all the variables

5x-(3(x+2))-8=0



We calculate terms in parentheses: -(3(x+2)), so:

3(x+2)

We multiply parentheses

3x+6

Back to the equation:

-(3x+6)



We get rid of parentheses

5x-3x-6-8=0

We add all the numbers together, and all the variables

2x-14=0

We move all terms containing x to the left, all other terms to the right

2x=14

x=14/2

x=7

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