3x+4+4(2x-8)=4(2x+3)+2

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Solution for 3x+4+4(2x-8)=4(2x+3)+2 equation: 



3x+4+4(2x-8)=4(2x+3)+2

We move all terms to the left:

3x+4+4(2x-8)-(4(2x+3)+2)=0

We multiply parentheses

3x+8x-(4(2x+3)+2)-32+4=0



We calculate terms in parentheses: -(4(2x+3)+2), so:

4(2x+3)+2

We multiply parentheses

8x+12+2

We add all the numbers together, and all the variables

8x+14

Back to the equation:

-(8x+14)



We add all the numbers together, and all the variables

11x-(8x+14)-28=0

We get rid of parentheses

11x-8x-14-28=0

We add all the numbers together, and all the variables

3x-42=0

We move all terms containing x to the left, all other terms to the right

3x=42

x=42/3

x=14

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