3x+4+4x=2(2x+11)

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Solution for 3x+4+4x=2(2x+11) equation: 



3x+4+4x=2(2x+11)

We move all terms to the left:

3x+4+4x-(2(2x+11))=0

We add all the numbers together, and all the variables

7x-(2(2x+11))+4=0



We calculate terms in parentheses: -(2(2x+11)), so:

2(2x+11)

We multiply parentheses

4x+22

Back to the equation:

-(4x+22)



We get rid of parentheses

7x-4x-22+4=0

We add all the numbers together, and all the variables

3x-18=0

We move all terms containing x to the left, all other terms to the right

3x=18

x=18/3

x=6

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