3x+4-(x+2)=6x+1/2(4x-8)

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Solution for 3x+4-(x+2)=6x+1/2(4x-8) equation: 



3x+4-(x+2)=6x+1/2(4x-8)

We move all terms to the left:

3x+4-(x+2)-(6x+1/2(4x-8))=0



Domain of the equation: 2(4x-8))!=0

x∈R



We get rid of parentheses

3x-x-(6x+1/2(4x-8))-2+4=0

We multiply all the terms by the denominator


3x*2(4x-8))-x*2(4x-8))-(6x+1-2*2(4x-8))+4*2(4x-8))=0

Wy multiply elements

12x^3(4-8))-(6x-2*2(4x-8))+4*2(4x+1-8))=0

We do not support expression: x^3(4

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