3x+4-2(-3x-8)=20-(-4x)+5x

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Solution for 3x+4-2(-3x-8)=20-(-4x)+5x equation: 



3x+4-2(-3x-8)=20-(-4x)+5x

We move all terms to the left:

3x+4-2(-3x-8)-(20-(-4x)+5x)=0

We multiply parentheses

3x+6x-(20-(-4x)+5x)+16+4=0



We calculate terms in parentheses: -(20-(-4x)+5x), so:

20-(-4x)+5x

determiningTheFunctionDomain
-(-4x)+5x+20

We add all the numbers together, and all the variables

5x-(-4x)+20

We get rid of parentheses

5x+4x+20

We add all the numbers together, and all the variables

9x+20

Back to the equation:

-(9x+20)



We add all the numbers together, and all the variables

9x-(9x+20)+20=0

We get rid of parentheses

9x-9x-20+20=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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