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3x+4-x-(-2)+x2=-1+x2+4x-(4+2x)
We move all terms to the left:
3x+4-x-(-2)+x2-(-1+x2+4x-(4+2x))=0
We add all the numbers together, and all the variables
3x-x+x2-(-1+x2+4x-(2x+4))+4-(-2)=0
We add all the numbers together, and all the variables
x^2+2x-(-1+x2+4x-(2x+4))+6=0
We calculate terms in parentheses: -(-1+x2+4x-(2x+4)), so:We get rid of parentheses
-1+x2+4x-(2x+4)
determiningTheFunctionDomain x2+4x-(2x+4)-1
We add all the numbers together, and all the variables
x^2+4x-(2x+4)-1
We get rid of parentheses
x^2+4x-2x-4-1
We add all the numbers together, and all the variables
x^2+2x-5
Back to the equation:
-(x^2+2x-5)
x^2-x^2+2x-2x+5+6=0
We add all the numbers together, and all the variables
11!=0
There is no solution for this equation
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