3x+4-x-(-2)+x2=-1+x2+4x-(4+2x)

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Solution for 3x+4-x-(-2)+x2=-1+x2+4x-(4+2x) equation: 



3x+4-x-(-2)+x2=-1+x2+4x-(4+2x)

We move all terms to the left:

3x+4-x-(-2)+x2-(-1+x2+4x-(4+2x))=0

We add all the numbers together, and all the variables

3x-x+x2-(-1+x2+4x-(2x+4))+4-(-2)=0

We add all the numbers together, and all the variables

x^2+2x-(-1+x2+4x-(2x+4))+6=0



We calculate terms in parentheses: -(-1+x2+4x-(2x+4)), so:

-1+x2+4x-(2x+4)

determiningTheFunctionDomain
x2+4x-(2x+4)-1

We add all the numbers together, and all the variables

x^2+4x-(2x+4)-1

We get rid of parentheses

x^2+4x-2x-4-1

We add all the numbers together, and all the variables

x^2+2x-5

Back to the equation:

-(x^2+2x-5)



We get rid of parentheses

x^2-x^2+2x-2x+5+6=0

We add all the numbers together, and all the variables

11!=0

There is no solution for this equation

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