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3x+4/2x=5
We move all terms to the left:
3x+4/2x-(5)=0
Domain of the equation: 2x!=0We multiply all the terms by the denominator
x!=0/2
x!=0
x∈R
3x*2x-5*2x+4=0
Wy multiply elements
6x^2-10x+4=0
a = 6; b = -10; c = +4;
Δ = b2-4ac
Δ = -102-4·6·4
Δ = 4
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$\sqrt{\Delta}=\sqrt{4}=2$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-10)-2}{2*6}=\frac{8}{12} =2/3 $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-10)+2}{2*6}=\frac{12}{12} =1 $
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