3x+4/4x+5=x-2/x-4

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Solution for 3x+4/4x+5=x-2/x-4 equation:


D( x )

x = 0

x = 0

x = 0

x in (-oo:0) U (0:+oo)

3*x+(4/4)*x+5 = x-(2/x)-4 // - x-(2/x)-4

3*x+(4/4)*x-x+2/x+4+5 = 0

3*x^1+2*x^-1+9*x^0 = 0

(3*x^2+9*x^1+2*x^0)/(x^1) = 0 // * x^2

x^1*(3*x^2+9*x^1+2*x^0) = 0

x^1

3*x^2+9*x+2 = 0

3*x^2+9*x+2 = 0

DELTA = 9^2-(2*3*4)

DELTA = 57

DELTA > 0

x = (57^(1/2)-9)/(2*3) or x = (-57^(1/2)-9)/(2*3)

x = (57^(1/2)-9)/6 or x = (-(57^(1/2)+9))/6

x in { (-(57^(1/2)+9))/6, (57^(1/2)-9)/6}

x in { (-(57^(1/2)+9))/6, (57^(1/2)-9)/6 }

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