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3x+4/5x+4=48
We move all terms to the left:
3x+4/5x+4-(48)=0
Domain of the equation: 5x!=0We add all the numbers together, and all the variables
x!=0/5
x!=0
x∈R
3x+4/5x-44=0
We multiply all the terms by the denominator
3x*5x-44*5x+4=0
Wy multiply elements
15x^2-220x+4=0
a = 15; b = -220; c = +4;
Δ = b2-4ac
Δ = -2202-4·15·4
Δ = 48160
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$
The end solution:
$\sqrt{\Delta}=\sqrt{48160}=\sqrt{16*3010}=\sqrt{16}*\sqrt{3010}=4\sqrt{3010}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-220)-4\sqrt{3010}}{2*15}=\frac{220-4\sqrt{3010}}{30} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-220)+4\sqrt{3010}}{2*15}=\frac{220+4\sqrt{3010}}{30} $
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