3x+4/8x-1X=2

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Solution for 3x+4/8x-1X=2 equation: 



3x+4/8x-1x=2

We move all terms to the left:

3x+4/8x-1x-(2)=0



Domain of the equation: 8x!=0

x!=0/8

x!=0

x∈R



We add all the numbers together, and all the variables

2x+4/8x-2=0

We multiply all the terms by the denominator


2x*8x-2*8x+4=0

Wy multiply elements

16x^2-16x+4=0

a = 16; b = -16; c = +4;
Δ = b2-4ac
Δ = -162-4·16·4
Δ = 0
Delta is equal to zero, so there is only one solution to the equation

                              Stosujemy wzór:
$x=\frac{-b}{2a}=\frac{16}{32}=1/2$

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