3x+40=11x-80

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Solution for 3x+40=11x-80 equation: 



3x+40=11x-80

We move all terms to the left:

3x+40-(11x-80)=0

We get rid of parentheses

3x-11x+80+40=0

We add all the numbers together, and all the variables

-8x+120=0

We move all terms containing x to the left, all other terms to the right

-8x=-120

x=-120/-8

x=+15

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