3x+40=3(4x+3)+4

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Solution for 3x+40=3(4x+3)+4 equation: 



3x+40=3(4x+3)+4

We move all terms to the left:

3x+40-(3(4x+3)+4)=0



We calculate terms in parentheses: -(3(4x+3)+4), so:

3(4x+3)+4

We multiply parentheses

12x+9+4

We add all the numbers together, and all the variables

12x+13

Back to the equation:

-(12x+13)



We get rid of parentheses

3x-12x-13+40=0

We add all the numbers together, and all the variables

-9x+27=0

We move all terms containing x to the left, all other terms to the right

-9x=-27

x=-27/-9

x=+3

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