3x+40=3(x+11)+7

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Solution for 3x+40=3(x+11)+7 equation: 



3x+40=3(x+11)+7

We move all terms to the left:

3x+40-(3(x+11)+7)=0



We calculate terms in parentheses: -(3(x+11)+7), so:

3(x+11)+7

We multiply parentheses

3x+33+7

We add all the numbers together, and all the variables

3x+40

Back to the equation:

-(3x+40)



We get rid of parentheses

3x-3x-40+40=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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