3x+40=7x+12

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Solution for 3x+40=7x+12 equation: 



3x+40=7x+12

We move all terms to the left:

3x+40-(7x+12)=0

We get rid of parentheses

3x-7x-12+40=0

We add all the numbers together, and all the variables

-4x+28=0

We move all terms containing x to the left, all other terms to the right

-4x=-28

x=-28/-4

x=+7

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