3x+42+5(x-3)=31

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Solution for 3x+42+5(x-3)=31 equation: 



3x+42+5(x-3)=31

We move all terms to the left:

3x+42+5(x-3)-(31)=0

We add all the numbers together, and all the variables

3x+5(x-3)+11=0

We multiply parentheses

3x+5x-15+11=0

We add all the numbers together, and all the variables

8x-4=0

We move all terms containing x to the left, all other terms to the right

8x=4

x=4/8

x=1/2

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