3x+42/6+x+18/5=12

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Solution for 3x+42/6+x+18/5=12 equation: 



3x+42/6+x+18/5=12

We move all terms to the left:

3x+42/6+x+18/5-(12)=0

determiningTheFunctionDomain
3x+x-12+42/6+18/5=0

We add all the numbers together, and all the variables

4x-5+18/5=0

We multiply all the terms by the denominator


4x*5+18-5*5=0

We add all the numbers together, and all the variables

4x*5-7=0

Wy multiply elements

20x-7=0

We move all terms containing x to the left, all other terms to the right

20x=7

x=7/20

x=7/20

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