3x+42=21x+12

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Solution for 3x+42=21x+12 equation: 



3x+42=21x+12

We move all terms to the left:

3x+42-(21x+12)=0

We get rid of parentheses

3x-21x-12+42=0

We add all the numbers together, and all the variables

-18x+30=0

We move all terms containing x to the left, all other terms to the right

-18x=-30

x=-30/-18

x=1+2/3

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