3x+4=10-3(x-2)

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Solution for 3x+4=10-3(x-2) equation: 



3x+4=10-3(x-2)

We move all terms to the left:

3x+4-(10-3(x-2))=0



We calculate terms in parentheses: -(10-3(x-2)), so:

10-3(x-2)

determiningTheFunctionDomain
-3(x-2)+10

We multiply parentheses

-3x+6+10

We add all the numbers together, and all the variables

-3x+16

Back to the equation:

-(-3x+16)



We get rid of parentheses

3x+3x-16+4=0

We add all the numbers together, and all the variables

6x-12=0

We move all terms containing x to the left, all other terms to the right

6x=12

x=12/6

x=2

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