3x+4=18+x(2)

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Solution for 3x+4=18+x(2) equation: 



3x+4=18+x(2)

We move all terms to the left:

3x+4-(18+x(2))=0

We add all the numbers together, and all the variables

-(+x^2+18)+3x+4=0

We get rid of parentheses

-x^2+3x-18+4=0

We add all the numbers together, and all the variables

-1x^2+3x-14=0

a = -1; b = 3; c = -14;
Δ = b2-4ac
Δ = 32-4·(-1)·(-14)
Δ = -47
Delta is less than zero, so there is no solution for the equation

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