3x+4=2(x+1)+x-1

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Solution for 3x+4=2(x+1)+x-1 equation: 



3x+4=2(x+1)+x-1

We move all terms to the left:

3x+4-(2(x+1)+x-1)=0



We calculate terms in parentheses: -(2(x+1)+x-1), so:

2(x+1)+x-1

We add all the numbers together, and all the variables

x+2(x+1)-1

We multiply parentheses

x+2x+2-1

We add all the numbers together, and all the variables

3x+1

Back to the equation:

-(3x+1)



We get rid of parentheses

3x-3x-1+4=0

We add all the numbers together, and all the variables

3!=0

There is no solution for this equation

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