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3x+4=2(x+2)-2x-4
We move all terms to the left:
3x+4-(2(x+2)-2x-4)=0
We calculate terms in parentheses: -(2(x+2)-2x-4), so:We add all the numbers together, and all the variables
2(x+2)-2x-4
We add all the numbers together, and all the variables
-2x+2(x+2)-4
We multiply parentheses
-2x+2x+4-4
We add all the numbers together, and all the variables
Back to the equation:
-()
3x=0
x=0/3
x=0
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