3x+4=2(x-2)+x+8

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Solution for 3x+4=2(x-2)+x+8 equation: 



3x+4=2(x-2)+x+8

We move all terms to the left:

3x+4-(2(x-2)+x+8)=0



We calculate terms in parentheses: -(2(x-2)+x+8), so:

2(x-2)+x+8

We add all the numbers together, and all the variables

x+2(x-2)+8

We multiply parentheses

x+2x-4+8

We add all the numbers together, and all the variables

3x+4

Back to the equation:

-(3x+4)



We get rid of parentheses

3x-3x-4+4=0

We add all the numbers together, and all the variables

=0

x=0/1

x=0

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