3x+4=6+x+3(x-2)

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Solution for 3x+4=6+x+3(x-2) equation: 



3x+4=6+x+3(x-2)

We move all terms to the left:

3x+4-(6+x+3(x-2))=0



We calculate terms in parentheses: -(6+x+3(x-2)), so:

6+x+3(x-2)

determiningTheFunctionDomain
x+3(x-2)+6

We multiply parentheses

x+3x-6+6

We add all the numbers together, and all the variables

4x

Back to the equation:

-(4x)



We add all the numbers together, and all the variables

-1x+4=0

We move all terms containing x to the left, all other terms to the right

-x=-4

x=-4/-1

x=+4

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