3x+4x+10x-3x+281-214=2x+67-20+4x

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Solution for 3x+4x+10x-3x+281-214=2x+67-20+4x equation:



3x+4x+10x-3x+281-214=2x+67-20+4x
We move all terms to the left:
3x+4x+10x-3x+281-214-(2x+67-20+4x)=0
We add all the numbers together, and all the variables
3x+4x+10x-3x-(6x+47)+281-214=0
We add all the numbers together, and all the variables
14x-(6x+47)+67=0
We get rid of parentheses
14x-6x-47+67=0
We add all the numbers together, and all the variables
8x+20=0
We move all terms containing x to the left, all other terms to the right
8x=-20
x=-20/8
x=-2+1/2

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