3x+4x+5x=x2+x+2+x+2+x+2

Solution for 3x+4x+5x=x2+x+2+x+2+x+2 equation:

3x+4x+5x=x2+x+2+x+2+x+2

We move all terms to the left:

3x+4x+5x-(x2+x+2+x+2+x+2)=0

We add all the numbers together, and all the variables

-(+x^2+3x+2+2+2)+3x+4x+5x=0

We add all the numbers together, and all the variables

-(+x^2+3x+2+2+2)+12x=0

We get rid of parentheses

-x^2-3x+12x-2-2-2=0

We add all the numbers together, and all the variables

-1x^2+9x-6=0

a = -1; b = 9; c = -6;
Δ = b2-4ac
Δ = 92-4·(-1)·(-6)
Δ = 57
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(9)-\sqrt{57}}{2*-1}=\frac{-9-\sqrt{57}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(9)+\sqrt{57}}{2*-1}=\frac{-9+\sqrt{57}}{-2}
$