3x+4x+6=9x2

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Solution for 3x+4x+6=9x2 equation:



3x+4x+6=9x^2
We move all terms to the left:
3x+4x+6-(9x^2)=0
determiningTheFunctionDomain -9x^2+3x+4x+6=0
We add all the numbers together, and all the variables
-9x^2+7x+6=0
a = -9; b = 7; c = +6;
Δ = b2-4ac
Δ = 72-4·(-9)·6
Δ = 265
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{265}}{2*-9}=\frac{-7-\sqrt{265}}{-18} $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{265}}{2*-9}=\frac{-7+\sqrt{265}}{-18} $

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