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3x+4x-3+16=2x*2x
We move all terms to the left:
3x+4x-3+16-(2x*2x)=0
We add all the numbers together, and all the variables
3x+4x-(+2x*2x)-3+16=0
We add all the numbers together, and all the variables
7x-(+2x*2x)+13=0
We get rid of parentheses
7x-2x*2x+13=0
Wy multiply elements
-4x^2+7x+13=0
a = -4; b = 7; c = +13;
Δ = b2-4ac
Δ = 72-4·(-4)·13
Δ = 257
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(7)-\sqrt{257}}{2*-4}=\frac{-7-\sqrt{257}}{-8} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(7)+\sqrt{257}}{2*-4}=\frac{-7+\sqrt{257}}{-8} $
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