3x+4x-3x-4x+6x-4x=1/50(100x+100)

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Solution for 3x+4x-3x-4x+6x-4x=1/50(100x+100) equation: 



3x+4x-3x-4x+6x-4x=1/50(100x+100)

We move all terms to the left:

3x+4x-3x-4x+6x-4x-(1/50(100x+100))=0



Domain of the equation: 50(100x+100))!=0

x∈R



We add all the numbers together, and all the variables

2x-(1/50(100x+100))=0

We multiply all the terms by the denominator


2x*50(100x+100))-(1=0

Wy multiply elements

100x^2(1=0

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