3x+4x-3x-4x+6x-4x=1/50(100x+100)

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Solution for 3x+4x-3x-4x+6x-4x=1/50(100x+100) equation:



3x+4x-3x-4x+6x-4x=1/50(100x+100)
We move all terms to the left:
3x+4x-3x-4x+6x-4x-(1/50(100x+100))=0
Domain of the equation: 50(100x+100))!=0
x∈R
We add all the numbers together, and all the variables
2x-(1/50(100x+100))=0
We multiply all the terms by the denominator
2x*50(100x+100))-(1=0
Wy multiply elements
100x^2(1=0

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