3x+5(-12+2/5x)=x+4(-12+2/5x)=15

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Solution for 3x+5(-12+2/5x)=x+4(-12+2/5x)=15 equation: 



3x+5(-12+2/5x)=x+4(-12+2/5x)=15

We move all terms to the left:

3x+5(-12+2/5x)-(x+4(-12+2/5x))=0



Domain of the equation: 5x)!=0

x!=0/1

x!=0

x∈R





Domain of the equation: 5x))!=0

x!=0/1

x!=0

x∈R



We add all the numbers together, and all the variables

3x+5(2/5x-12)-(x+4(2/5x-12))=0

We multiply parentheses

3x+10x-(x+4(2/5x-12))-60=0

We multiply all the terms by the denominator


3x*5x-12))+10x*5x-12))-(x+4(2-60*5x-12))=0

We add all the numbers together, and all the variables

3x*5x-12))+10x*5x-12))-(x+4(-60*5x-10))=0

Wy multiply elements

15x^2-12))+10x*5x-12))-(x+4(-60*5x-10))=0

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