3x+5(1-x)-5(1+2x)=6+7(1+x)-(1-x)

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Solution for 3x+5(1-x)-5(1+2x)=6+7(1+x)-(1-x) equation: 



3x+5(1-x)-5(1+2x)=6+7(1+x)-(1-x)

We move all terms to the left:

3x+5(1-x)-5(1+2x)-(6+7(1+x)-(1-x))=0

We add all the numbers together, and all the variables

3x+5(-1x+1)-5(2x+1)-(6+7(x+1)-(-1x+1))=0

We multiply parentheses

3x-5x-10x-(6+7(x+1)-(-1x+1))+5-5=0



We calculate terms in parentheses: -(6+7(x+1)-(-1x+1)), so:

6+7(x+1)-(-1x+1)

determiningTheFunctionDomain
7(x+1)-(-1x+1)+6

We multiply parentheses

7x-(-1x+1)+7+6

We get rid of parentheses

7x+1x-1+7+6

We add all the numbers together, and all the variables

8x+12

Back to the equation:

-(8x+12)



We add all the numbers together, and all the variables

-12x-(8x+12)=0

We get rid of parentheses

-12x-8x-12=0

We add all the numbers together, and all the variables

-20x-12=0

We move all terms containing x to the left, all other terms to the right

-20x=12

x=12/-20

x=-3/5

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