3x+5(2-3x)=7-2(x+3)

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Solution for 3x+5(2-3x)=7-2(x+3) equation: 



3x+5(2-3x)=7-2(x+3)

We move all terms to the left:

3x+5(2-3x)-(7-2(x+3))=0

We add all the numbers together, and all the variables

3x+5(-3x+2)-(7-2(x+3))=0

We multiply parentheses

3x-15x-(7-2(x+3))+10=0



We calculate terms in parentheses: -(7-2(x+3)), so:

7-2(x+3)

determiningTheFunctionDomain
-2(x+3)+7

We multiply parentheses

-2x-6+7

We add all the numbers together, and all the variables

-2x+1

Back to the equation:

-(-2x+1)



We add all the numbers together, and all the variables

-12x-(-2x+1)+10=0

We get rid of parentheses

-12x+2x-1+10=0

We add all the numbers together, and all the variables

-10x+9=0

We move all terms containing x to the left, all other terms to the right

-10x=-9

x=-9/-10

x=9/10

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