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3x+5(2x-1)=6(2x+3)
We move all terms to the left:
3x+5(2x-1)-(6(2x+3))=0
We multiply parentheses
3x+10x-(6(2x+3))-5=0
We calculate terms in parentheses: -(6(2x+3)), so:We add all the numbers together, and all the variables
6(2x+3)
We multiply parentheses
12x+18
Back to the equation:
-(12x+18)
13x-(12x+18)-5=0
We get rid of parentheses
13x-12x-18-5=0
We add all the numbers together, and all the variables
x-23=0
We move all terms containing x to the left, all other terms to the right
x=23
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