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3x+5(2x-3)=3(x+3)
We move all terms to the left:
3x+5(2x-3)-(3(x+3))=0
We multiply parentheses
3x+10x-(3(x+3))-15=0
We calculate terms in parentheses: -(3(x+3)), so:We add all the numbers together, and all the variables
3(x+3)
We multiply parentheses
3x+9
Back to the equation:
-(3x+9)
13x-(3x+9)-15=0
We get rid of parentheses
13x-3x-9-15=0
We add all the numbers together, and all the variables
10x-24=0
We move all terms containing x to the left, all other terms to the right
10x=24
x=24/10
x=2+2/5
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