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3x+5(7x-3)=9(x-5)
We move all terms to the left:
3x+5(7x-3)-(9(x-5))=0
We multiply parentheses
3x+35x-(9(x-5))-15=0
We calculate terms in parentheses: -(9(x-5)), so:We add all the numbers together, and all the variables
9(x-5)
We multiply parentheses
9x-45
Back to the equation:
-(9x-45)
38x-(9x-45)-15=0
We get rid of parentheses
38x-9x+45-15=0
We add all the numbers together, and all the variables
29x+30=0
We move all terms containing x to the left, all other terms to the right
29x=-30
x=-30/29
x=-1+1/29
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