3x+5(x+5)=(2x+2)+27

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Solution for 3x+5(x+5)=(2x+2)+27 equation: 



3x+5(x+5)=(2x+2)+27

We move all terms to the left:

3x+5(x+5)-((2x+2)+27)=0

We multiply parentheses

3x+5x-((2x+2)+27)+25=0



We calculate terms in parentheses: -((2x+2)+27), so:

(2x+2)+27

We get rid of parentheses

2x+2+27

We add all the numbers together, and all the variables

2x+29

Back to the equation:

-(2x+29)



We add all the numbers together, and all the variables

8x-(2x+29)+25=0

We get rid of parentheses

8x-2x-29+25=0

We add all the numbers together, and all the variables

6x-4=0

We move all terms containing x to the left, all other terms to the right

6x=4

x=4/6

x=2/3

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