3x+5(x-2)=10+2x+16

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Solution for 3x+5(x-2)=10+2x+16 equation: 



3x+5(x-2)=10+2x+16

We move all terms to the left:

3x+5(x-2)-(10+2x+16)=0

We add all the numbers together, and all the variables

3x+5(x-2)-(2x+26)=0

We multiply parentheses

3x+5x-(2x+26)-10=0

We get rid of parentheses

3x+5x-2x-26-10=0

We add all the numbers together, and all the variables

6x-36=0

We move all terms containing x to the left, all other terms to the right

6x=36

x=36/6

x=6

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