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3x+5(x-4)=-3(x-5)
We move all terms to the left:
3x+5(x-4)-(-3(x-5))=0
We multiply parentheses
3x+5x-(-3(x-5))-20=0
We calculate terms in parentheses: -(-3(x-5)), so:We add all the numbers together, and all the variables
-3(x-5)
We multiply parentheses
-3x+15
Back to the equation:
-(-3x+15)
8x-(-3x+15)-20=0
We get rid of parentheses
8x+3x-15-20=0
We add all the numbers together, and all the variables
11x-35=0
We move all terms containing x to the left, all other terms to the right
11x=35
x=35/11
x=3+2/11
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