3x+5(x2)=14

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Solution for 3x+5(x2)=14 equation:



3x+5(x2)=14
We move all terms to the left:
3x+5(x2)-(14)=0
We add all the numbers together, and all the variables
5x^2+3x-14=0
a = 5; b = 3; c = -14;
Δ = b2-4ac
Δ = 32-4·5·(-14)
Δ = 289
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{289}=17$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(3)-17}{2*5}=\frac{-20}{10} =-2 $
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(3)+17}{2*5}=\frac{14}{10} =1+2/5 $

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