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3x+5+2x=5(x+1)
We move all terms to the left:
3x+5+2x-(5(x+1))=0
We add all the numbers together, and all the variables
5x-(5(x+1))+5=0
We calculate terms in parentheses: -(5(x+1)), so:We get rid of parentheses
5(x+1)
We multiply parentheses
5x+5
Back to the equation:
-(5x+5)
5x-5x-5+5=0
We add all the numbers together, and all the variables
=0
x=0/1
x=0
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