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3x+5+4x=7(x+5/7)
We move all terms to the left:
3x+5+4x-(7(x+5/7))=0
We add all the numbers together, and all the variables
3x+4x-(7(+x+5/7))+5=0
We add all the numbers together, and all the variables
7x-(7(+x+5/7))+5=0
We multiply all the terms by the denominator
7x*7))-(7(+x+5+5*7))=0
We add all the numbers together, and all the variables
7x*7))-(7(x+40))=0
We add all the numbers together, and all the variables
7x*7))-(7(x=0
Wy multiply elements
49x^2=0
a = 49; b = 0; c = 0;
Δ = b2-4ac
Δ = 02-4·49·0
Δ = 0
Delta is equal to zero, so there is only one solution to the equation
Stosujemy wzór:$x=\frac{-b}{2a}=\frac{0}{98}=0$
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