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3x+5-x=10-(5+x)
We move all terms to the left:
3x+5-x-(10-(5+x))=0
We add all the numbers together, and all the variables
3x-x-(10-(x+5))+5=0
We add all the numbers together, and all the variables
2x-(10-(x+5))+5=0
We calculate terms in parentheses: -(10-(x+5)), so:We get rid of parentheses
10-(x+5)
determiningTheFunctionDomain -(x+5)+10
We get rid of parentheses
-x-5+10
We add all the numbers together, and all the variables
-1x+5
Back to the equation:
-(-1x+5)
2x+1x-5+5=0
We add all the numbers together, and all the variables
3x=0
x=0/3
x=0
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