3x+5=10+x2

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Solution for 3x+5=10+x2 equation: 



3x+5=10+x2

We move all terms to the left:

3x+5-(10+x2)=0

We add all the numbers together, and all the variables

-(+x^2+10)+3x+5=0

We get rid of parentheses

-x^2+3x-10+5=0

We add all the numbers together, and all the variables

-1x^2+3x-5=0

a = -1; b = 3; c = -5;
Δ = b2-4ac
Δ = 32-4·(-1)·(-5)
Δ = -11
Delta is less than zero, so there is no solution for the equation

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