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3x+5=2(2x-3)+2(x)
We move all terms to the left:
3x+5-(2(2x-3)+2(x))=0
We calculate terms in parentheses: -(2(2x-3)+2x), so:We get rid of parentheses
2(2x-3)+2x
We add all the numbers together, and all the variables
2x+2(2x-3)
We multiply parentheses
2x+4x-6
We add all the numbers together, and all the variables
6x-6
Back to the equation:
-(6x-6)
3x-6x+6+5=0
We add all the numbers together, and all the variables
-3x+11=0
We move all terms containing x to the left, all other terms to the right
-3x=-11
x=-11/-3
x=3+2/3
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